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[–] cyberpunk 0 points 2 points (+2|-0) ago 

You'd kill one of each color?

[–] [deleted] 0 points 1 point (+1|-0) ago 

[Deleted]

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[–] Danbear 0 points 1 point (+1|-0) ago 

What color depth? 256? 8 bit? 16 bit? God not 32 bit!

Now I'm curious if you could afford to do any of those...

The cheapest Ferrari I could easily find costs: $198,973 (2015 Ferrari Califonia)

256 ferraris would cost: $50,937,088 So you could do all the colors and have (a lot of) money to spare!

8 bit color has a total of 16.8 million shades of color, so you would spend: $3,342,746,400,000
That is 3.4 Trillion dollars. Sorry, can't do all the colors...

16 bit color has about 281 trillion shades. Now my calc is going to start giving me issues with number size, so from here out numbers wont be exact...
2.81x10^14 * 2x10^5 = 5.62x10^19 or $56,200,000,000,000,000,000

I need to google to learn what that number even is called...

56.2 QUINTILLION dollars. And that is just for 16 bit color.

32 bit color is calculated a bit differently and depending on which formula you use changes the total dramatically. If we treat it like we did 8 bit and 16 bit color, then each primary (R, G B) gets 32 bits of data each, then that is multiplied by each other. So do (2^32)^3 that will be how many possible color shades. But I'll tell you now, it way way WAY more shades than the human eye can see.

The most common way 32 bit color is handled is to use the first 24 bits to hold the color data, then the last 8 to hold alpha transparency. The end result is something closer to 16 bit color + transparency.