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The original problem was 6 ÷ 2(1+2).
I suppose it is a question of notation, but I think that 6 / (2*3) = 6 ÷ 2(3) because of the short hand notation of leaving the multiplication sign from the second term makes the 2 seem like a coefficient belonging to that term.
6 / 2 * 3 could be 9, but again it is a limitation of one line typing creating the ambiguity, so that to type it one would type 6 / (2 * 3) if the multiple of 3 were in the denominator, but when one writes it 6 / 2(3), it creates the impression that the 2 is a coefficient the 3 parenthetical group.
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[–] 16082660? ago
The original problem was 6 ÷ 2(1+2).
I suppose it is a question of notation, but I think that 6 / (2*3) = 6 ÷ 2(3) because of the short hand notation of leaving the multiplication sign from the second term makes the 2 seem like a coefficient belonging to that term.
6 / 2 * 3 could be 9, but again it is a limitation of one line typing creating the ambiguity, so that to type it one would type 6 / (2 * 3) if the multiple of 3 were in the denominator, but when one writes it 6 / 2(3), it creates the impression that the 2 is a coefficient the 3 parenthetical group.
For clarity parenthesises should be used.